7b^2-27b-4=0

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Solution for 7b^2-27b-4=0 equation:



7b^2-27b-4=0
a = 7; b = -27; c = -4;
Δ = b2-4ac
Δ = -272-4·7·(-4)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-29}{2*7}=\frac{-2}{14} =-1/7 $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+29}{2*7}=\frac{56}{14} =4 $

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